2022大学慕课答案 Engineering Mechanics(河南理工大学) 最新大学MOOC满分章节测试答案
本答案对应课程为:点我自动跳转查看
本课程起止时间为:2020-02-17到2020-07-06
本篇答案更新状态:已完结
01 Reductions of force systems Tests for week 1
1、 问题:As shown in the parallelogram, all forces are at point A. In which figure FR can be considered as the resultant of F1 and F2?
选项：
A:
B:
C:
D:
答案: 【】
2、 问题:Neglect the weights of all members. In which case bar BD is not a two-force member?
选项：
A:
B:
C:
D:
答案: 【】
3、 问题:To study the whole system, which free-body diagram is correct? 
选项：
A:
B:
C:
D:
答案: 【】
4、 问题:To study the whole system, which free-body diagram is correct?
选项：
A:
B:
C:
D:
答案: 【】
5、 问题:To study the whole system, which free-body diagram is correct? 
选项：
A:
B:
C:
D:
答案: 【】
6、 问题:For bar AD, which free-body diagram
is correct? 
选项：
A:
B:
C:
D:
答案: 【】
7、 问题:In this equilibrium mechanism, the free-body diagram of crank OA can be drawn as
选项：
A:
B:
C:
D:
答案: 【;
;
】
8、 问题:The resultant force of two intersecting forces 
and 
is 
, i.e., 
. The magnitude of must be larger than those of and .
选项：
A:正确
B:错误
答案: 【错误】
分析：【FR is the vector summation of F1 and F2, so it’s magnitude could be larger or smaller than those of F1 and F2.】
9、 问题:As long as two forces have the same magnitude and are in opposite directions, these two forces form a couple.
选项：
A:正确
B:错误
答案: 【错误】
分析：【They must be separated by a perpendicular distance.】
10、 问题:For any coplanar force system, as long as its principal vector is not equal to zero, the force system can be reduced to one single force.
选项：
A:正确
B:错误
答案: 【正确】
02 Equilibrium of force systems Tests for week 2
1、 问题:All weights and frictions can be neglected. If a force P is applied at the mid-point of bar AB, in which case the bar can be in a equilibrium state?
选项：
A:
B:
C:
D:
答案: 【】
2、 问题:A rigid body is in equilibrium state under the coplanar force system. Which set of equilibrium equations are not independent of each other? 
选项：
A:SX = 0, Sx = 0, SmA(F) = 0
B:SmO(F) = 0, SmA(F) = 0, SmB(F) = 0
C:SmO(F) = 0, SmC(F) = 0, SY = 0
D:SX = 0, SY = 0, SmO(F) = 0
答案: 【SmO(F) = 0, SmA(F) = 0, SmB(F) = 0】
3、 问题:A rigid body is in equilibrium state under the coplanar force system. Which set of equilibrium equations are not independent of each other?
选项：
A:SX = 0, SmO(F) = 0, SmA(F) = 0
B:SmO(F) = 0, SmA(F) = 0, SmB(F) = 0
C:SmA(F) = 0, SmC(F) = 0, SY = 0
D:SX = 0, SmA(F) = 0, SmB(F) = 0
答案: 【SX = 0, SmA(F) = 0, SmB(F) = 0】
4、 问题:Consider the equilibrium of bar AB. The correct moment equation about point A should be 
选项：
A:SmA(F) = m + Psinq × L/2 + M + mA = 0
B:SmA(F) = -m – Psinq × L/2 + M = 0
C:SmA(F) = -mL – P × L/2 + M + mA = 0
D:SmA(F) = -m – Psinq × L/2 + M + mA = 0
答案: 【SmA(F) = -m – Psinq × L/2 + M + mA = 0】
5、 问题:The whole system is in equilibrium state. Which set of equilibrium equations is correct? 
选项：
A:Study ADB： åmA(F) = NB×2L + YD×L = 0
B:Study the whole system： åmA(F) = – P×(L+r) + NB×2L = 0
C:Study CDE and the pully： åmD(F) = – P×r – T×(L – r) + XE×L + SBC×L×sin30° = 0
D:Study the whole system： åmA(F) = – P×(L+r) + NB×2L – T×(L – r) = 0
答案: 【Study the whole system： åmA(F) = – P×(L+r) + NB×2L – T×(L – r) = 0】
6、 问题:A planar mechanism consists of three rigid bodies and is subjected to a force system in its plane. How many independent equilibrium equations can be created at most?
选项：
A:6
B:9
C:12
D:3
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